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What is the axis of symmetry and vertex for the graph #y=8(x-10)^2-16#?

1 Answer

Aug 9, 2017

Vertex is at #(10 ,-16) #
Axis of symmetry is # x= 10#

Explanation:

#y= 8(x-10)^2 -16 # . Comparing with standard vertex form of

equation #y=a(x-h)^2+k ; (h,k)# being vertex , we find here

# h=10 ,k=-16 # . So vertex is at #(10 ,-16) #

Axis of symmetry is # x= h or x= 10#

graph{8(x-10)^2-16 [-40, 40, -20, 20]} [Ans]

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