# What is the average value of a function #f(x) = 2x sec2 x# on the interval #[0, pi/4]#?

##### 1 Answer

Aug 19, 2017

There isn't one

#### Explanation:

Recall that

Thus,

Attempting to find the average value using an integral:

#1/(pi//4-0)int_0^(pi//4)2xsec(2x)dx#

is impossible because the integral diverges.