What is the antiderivative of #x^(1/2)#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Eddie Jul 5, 2016 #= (2 x^(3/2))/3# Explanation: use the power rule #int dx qquad x^n = (x^(n+1))/(n+1)# so here it #int dx qquad x^(1/2) = (x^((1/2)+1))/((1/2)+1)# #= (2 x^(3/2))/3# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 26199 views around the world You can reuse this answer Creative Commons License