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What is the antiderivative of #cos^2 x#?

1 Answer

May 13, 2018

#x/2+1/4sin2x+C#

Explanation:

Recall the cosine power reduction formula,

#cos^2x=1/2(1+cos2x)#

Then,

#intcos^2xdx=1/2int(1+cos2xdx)=1/2(intdx+intcos2xdx)#

#=1/2(x+1/2sin2x+C)=x/2+1/4sin2x+C#

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