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What is the antiderivative of #-5e^(x-1)#?

1 Answer

Gió · Antoine

Jul 23, 2015

I found: #-5e^(x-1)+c#

Explanation:

You have:
#int-5e^(x-1)dx=-5inte^(x-1)dx=#
but #d[(x-1)]=dx# so you can write:
#-5inte^(x-1)d(x-1)=#
#=-5e^(x-1)+c#

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