What is #sqrt106# in simplified radical form?

1 Answer
George C.
Aug 9, 2017

#sqrt(106)# is already in simplified radical form.

Explanation:

Factoring #106# we find:

#106 = 2*53#

It has no square factors and hence there is no factor we can separate out and bring outside the radical.

We could write:

#sqrt(106) = sqrt(2*53) = sqrt(2)sqrt(53)#

but that is not (usually) considered simplified.

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