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What is #lim_(xrarrpi/2) e^(-tan^2x# ?

1 Answer

Feb 4, 2018

#lim_(x->pi/2)e^(-tan^2x)=0#

Explanation:

Since

#lim_(x->pi/2)tanx=+oo#

we get

#lim_(x->pi/2)tan^2x=+oo#

#lim_(x->pi/2)-tan^2x=-oo#

#lim_(x->pi/2)e^(-tan^2x)=e^-oo=1/e^(+oo)=1/oo=0#

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