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What is the derivative of #sin^3x#?

1 Answer

Mar 3, 2018

Basic formula:

#d/(dx)x^n=nx^(n-1)#

#d/dx(sinx)=cosx#

Now, let's move to the question:
#color(white)=d/dx(sin^3x)#
#=(3sin^2x)×(d/dx(sinx))#
#=3sin^2xcosx#

It may be useful for you👍

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