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What is #int 4 x^5 -7 x^4 + 9 x^3 -8 x^2 -3 x + 5 dx#?

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1 Answer

Leland Adriano Alejandro

Jan 12, 2016

#(2/3)x^6-(7/5)x^5+(9/4)x^4-(8/3)x^3-(3/2)x^2+5x+C#

Explanation:

Use the power formula #int x^n# #dx#=#x^(n+1)/(n+1)# for each term of the polynomial

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