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What is #int 2sec^2xtanxdx#?

1 Answer

Nov 25, 2015

#[tan^2(x)]+C#

Explanation:

#2intsec^2(x)tan(x) dx#

#t = tan(x)#
#dt = sec^2(x)dx#

#2inttdt#

#[t^2]+C#

And then substitute back

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