What is a solution to the differential equation #dy/dx=x/y#?
1 Answer
Nov 16, 2016
# y^2 = x^2 + C #
Explanation:
This is a First Order Separable Differential Equation, we can "separate the variables" to give;
# intydy = intxdx #
Integrating we get:
# 1/2y^2 = 1/2x^2 + A #
# :. y^2 = x^2 + 2A #
# :. y^2 = x^2 + C #
