What is a solution to the differential equation dy/dx =( 2csc^2 x)/ (cot x)?
2 Answers
Dec 8, 2016
Explanation:
The equation simplifies:
Separate variables:
Integrate:
Dec 8, 2016
Explanation:
First we should separate the variables, which means that we can treat
dy=(2csc^2x)/cotxdx
Now integrate both sides:
intdy=2intcsc^2x/cotxdx
On the right hand side, let
y=-2int(-csc^2x)/cotxdx
y=-2int(du)/u
y=-2lnabsu+C
y=-2lnabscotx+C
One possible simplification we could make if we wanted would be to bring the
y=2lnabstanx+C