What is 4 square root of 80? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Aron S. Sep 20, 2015 #4sqrt(80) = 16sqrt(5)# Explanation: Simplify/solve it by finding factors of #80# that are perfect squares and can be moved out of the radical sign. #4sqrt(80) = 4sqrt(16*5) = 4sqrt(16)sqrt(5)= 4*4sqrt(5)= 16sqrt(5)# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 9181 views around the world You can reuse this answer Creative Commons License