It is not comfortable to divide BY a decimal, so we multiply by powers of #10# to change what the question looks like.
#0.89 div 5.60 = 0.89/5.6#
#0.89/5.6 xx10/10 = 8.9/56" "rarr (10/10 = 1)#so the value stays the same.
Now you can divide as usual because the denominator is a whole number, not a decimal fraction.
#color(white)(........x.........)ul(0.1589)#
#color(white)(..............)56)8.9000#
#color(white)(....................)ul56#
#color(white)(....................)330#
#color(white)(....................)ul280#
#color(white)(.......................)500#
#color(white)(.......................)ul448#
#color(white)(..........................)520#
#color(white)(..........................)ul504#
The answer is a recurring decimal. From this answer we can round off to 3 decimal places to get #0.159#
