#"Molarity"##=##"Moles of solute"/"Volume of Solution"#
Explanation:
Or #C("concentration")=n/V#, where #n# is the amount of substance in moles, and #V# is the volume of the solution.
The units of concentration are simply #mol*L^-1#. And thus #"volume "xx" concentration"##=##n#, i.e. moles of solute. Doing calculations myself, I still use the relationship #C=n/V# habitually to do stoichiometry problems.