What does (6+4i)/(3-i) equal?

1 Answer
Gió
Oct 21, 2015

I found: 7/5+9/5i

Explanation:

In this case you need to first change the denominator into a pure real number; to do that you need to multiply and divide by the complex conjugate of the denominator, i.e.:
(6+4i)/(3-i)*color(red)((3+i)/(3+i))=
((6+4i)(3+i))/(9+1)= where you used the fact that i^2=-1
and:
(18+6i+12i-4)/10=14/10+18/10i=7/5+9/5i

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