What does (1+3i)/(2+2i) equal in a+bi form?

1 Answer
Gió
Oct 21, 2015

I found: 1+1/2i

Explanation:

First multiply and divide by the complex conjugate of the denominator to get a Pure Real denominator:
(1+3i)/(2+2i)*color(red)((2-2i)/(2-2i))=
=((1+3i)(2-2i))/(4+4)=(2-2i+6i-6i^2)/8=
but i^2=-1
(8+4i)/8=8/8+4/8i=1+1/2i

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