What are the x-intercepts of #y = x^2 - 4x - 12#?

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Answer 1 · 2015-10-28T13:45:47

Y intercept = -12
X-intercept = 6,-2

For the intercepts, you need to understand first what means x-intercept and y-intercept.

X intercept means the point at which the line or the curve that intersects x-axis, and y intercept is the intersection at y-axis.

For the y intercept,
we know at y-axis, x=0

SO,

y =#0^2 -4*0 -12#

= -12

So -12 is the y-intercept,

For the x-intercept, we let y=0

#x^2 -4x-12#=0

#x^2 -(6-2) -12#=0

#x^2 -6x + 2x -12#=0

#x(x-6) +2(x-6)#=0

(x-6)(x+2) =0

So either Or.
x-6=0 x+2 =0
x=6 x=-2

So 6 and -2 are the x-intercepts.