What are the x- and y-intercepts of $y = \sqrt{x + 2}$ $y=sqrt(x+2)$ ?

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Answer 1 · 2015-07-09T20:52:40

$(0, \sqrt{2}), (- 2, 0)$ $(0, sqrt 2), (-2, 0)$

$x = 0 \Rightarrow y = \sqrt{0 + 2}$ $x = 0 \Rightarrow y = sqrt(0 + 2)$

$y = 0 \Rightarrow 0 = \sqrt{x + 2}$ $y = 0 \Rightarrow 0 = \sqrt(x + 2)$

$0^{2} = x + 2$ $0^2 = x + 2$

$0^{2} - 2 = x$ $0^2 - 2 = x$

What are the x- and y-intercepts of y=√x+2y=sqrt(x+2)?