What are the x- and y-intercepts of $y=sqrt(2x-1)$ ?

Question

9421 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-16T22:06:03

There is no intercept with the $y$ axis.

The intercept with the $x$ axis is at $(1/2, 0)$

If $y = sqrt(2x-1)$ intercepted the $y$ axis, then it would be where $x=0$ , but then $y = sqrt(-1)$ is not defined in $RR$ .

In fact, $y = sqrt(2x-1)$ is only defined for $x >= 1/2$ .

If $y = 0$ then $2x - 1 = 0$ so $x = 1/2$ . So the intercept with the $x$ axis is at $(1/2, 0)$

graph{sqrt(2x-1) [-10, 10, -5, 5]}

What are the x- and y-intercepts of y=sqrt(2x-1)y=sqrt(2x-1)?