What are the values and types of the critical points, if any, of f(x)=x^3-6x^2+12x-6?
1 Answer
Mar 13, 2017
Explanation:
Start by differentiating.
f'(x) = 3x^2 - 12x + 12
f'(x) = 3(x^2 - 4x + 4)
f'(x) = (x- 2)^2
Set this to
0= (x - 2)^2
x - 2 = 0
x = 2
Therefore, there will be one critical value at
Hopefully this helps!