What are the values and types of the critical points, if any, of #f(x)=x^3-6x^2+12x-6#?
1 Answer
Mar 13, 2017
Explanation:
Start by differentiating.
#f'(x) = 3x^2 - 12x + 12#
#f'(x) = 3(x^2 - 4x + 4)#
#f'(x) = (x- 2)^2#
Set this to
#0= (x - 2)^2#
#x - 2 = 0#
#x = 2#
Therefore, there will be one critical value at
Hopefully this helps!
