What are the solution(s) of $2x^2 - 2x = 1$ ?

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Answer 1 · 2015-11-06T15:50:56

The approximate values are 1.37 and -0.37

Rewrite your original equation by moving the constant to the left side of the equation:
$2x^2 - 2x - 1 = 0$

Here you have a typical $ax^2 + bx + c = 0$ equation.
Use the ABC-formula to solve the equation.

$(-b +- sqrt(b^2 - 4ac))/(2a)$

Fill in 2 as a, -2 as b and -1 as c.

You can also use a quadratic equation calculator on line, for example: http://www.math.com/students/calculators/source/quadratic.htm

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