What are the intercepts of $y = - 2 {(x + 3)}^{2} + 25$ $y=-2(x+3)^2+25$ ?

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What are the intercepts of $y = - 2 {(x + 3)}^{2} + 25$ $y=-2(x+3)^2+25$ ?

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Answer 1 · 2016-03-11T11:31:43

Y-intercept is at (0,7) ; X-intercepts are at $(\frac{5}{\sqrt{2}} - 3, 0) and (- \frac{5}{\sqrt{2}} - 3, 0)$ $(5/sqrt2-3,0) and (-5/sqrt2-3,0)$

Explanation:

Y-intercept: putting x=0 in the equation we get $y = - 2 \cdot 9 + 25 = 7$ $y= -2*9+25=7$ So Y-intercept is at (0,7); X-ntercept : putting y=0 in the equation we get $2 {(x + 3)}^{2} = 25 or {(x + 3)}^{2} = \frac{25}{2} or x + 3 = \frac{5}{\sqrt{2}} or x + 3 = - \frac{5}{\sqrt{2}} or x = - 3 + \frac{5}{\sqrt{2}} or x = - 3 - \frac{5}{\sqrt{2}}$ $2(x+3)^2=25 or (x+3)^2=25/2 or x+3 = 5/sqrt 2 or x+3 = -5/sqrt2 or x=-3+5/sqrt2 or x= -3-5/sqrt2$ graph{-2(x+3)^2+25 [-80, 80, -40, 40]}[Ans]

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What are the intercepts of $y = - 2 {(x + 3)}^{2} + 25$ $y=-2(x+3)^2+25$ ?

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What are the intercepts of y=−2(x+3)2+25y=-2(x+3)^2+25?

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What are the intercepts of $y = - 2 {(x + 3)}^{2} + 25$ $y=-2(x+3)^2+25$ ?