What are the intercepts of #y=-2(x+3)^2+25#?

1 Answer
Binayaka C.
Mar 11, 2016

Y-intercept is at (0,7) ; X-intercepts are at #(5/sqrt2-3,0) and (-5/sqrt2-3,0)#

Explanation:

Y-intercept: putting x=0 in the equation we get #y= -2*9+25=7# So Y-intercept is at (0,7); X-ntercept : putting y=0 in the equation we get #2(x+3)^2=25 or (x+3)^2=25/2 or x+3 = 5/sqrt 2 or x+3 = -5/sqrt2 or x=-3+5/sqrt2 or x= -3-5/sqrt2# graph{-2(x+3)^2+25 [-80, 80, -40, 40]}[Ans]

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