What are the components of the vector between the origin and the polar coordinate (14, (11pi)/6)?

1 Answer
Apr 24, 2018

(x,y) = ( 7 sqrt{3}, -7 )

Explanation:

Oh my, it's like trig only has two triangles. Every one of these problems will be a variant of 30^circ or 45^circ. This one's 30^circ.

(x,y) = (r cos theta, r sin theta)

= (14 cos( {11 pi}/6 ) , 14 sin( {11 pi}/6 ) )

= ( 14 cos(pi/6), - 14 sin(pi/6) )

= (14 (sqrt{3}/2), -14 (1/2) )

= ( 7 sqrt{3}, -7 )