How do you find the length and direction of vector #2 - 4i#?

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Answer 1 · 2018-07-03T04:13:22

Length of the vector #2-4i#

#=\sqrt{2^2+(-4)^2}#

#=2\sqrt5#

And the angle #\theta# in CCW with the positive x-axis

#\theta=-\tan^{-1}|-4/2|#

#=-\tan^{-1}(2)#

#=-63.435^\circ#