What are the components of the vector between the origin and the polar coordinate (2, (7pi)/4)?

1 Answer
A. S. Adikesavan
Feb 16, 2016

Components of this vector from the origin are
{sqrt 2, - sqrt 2j

Explanation:

r = 2 and theta = 7pi/4.
The radial line theta = 7pi/4 bisects the fourth quadrant..
x = 2 cos 7pi/4 =2 cos (2pi - pi/4) = 2 cos (pi/4) = sqrt 2. Similarly, y = 2 sin 7pi/4 =2sin (2pi - pi/4) = - 2 sin (pi/4) = - sqrt2.
The given radial vector has components (x, y) = (sqrt2, - sqrt2)

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