What are the components of the vector between the origin and the polar coordinate (-8, (5pi)/3)?

1 Answer
bp
Feb 6, 2016

-4i +4sqrt3 j

Explanation:

In cartesian coordinates x= rcos theta. In this case it would be x=-8 cos ((5pi)/3)= -8cos (-pi/3)= -4 and y= r sin theta= -8 sin((5pi)/3)= -8 sin (-pi/3)= 4sqrt3 . The point would lie in 2nd quadrant.

Its vector form would be -4i +4sqrt3 j

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