What are the components of the vector between the origin and the polar coordinate (2, (19pi)/12)?

1 Answer
Mar 12, 2016

=>vecA=2cos(5pi/12)hati-2sin(5pi/12)hatj

Explanation:

If polar coordinate of a position vector vecA w.r.t origin is (r,theta) then vecA=rcosthetahati+rsinthetahatj
In our problem r=2 andtheta =19pi/12

so vecA=2cos(19pi/12)hati+2sin(19pi/12)hatj
=>vecA=2cos(2pi-5pi/12)hati+2sin(2pi-5pi/12)hatj
=>vecA=2cos(5pi/12)hati-2sin(5pi/12)hatj