What are the components of the vector between the origin and the polar coordinate (6, (17pi)/12)?
1 Answer
Mar 7, 2016
Explanation:
Using the formulae that links Polar to Cartesian coordinates.
• x = rcostheta
• y = rsintheta here r = 6 and
theta = (17pi)/12 hence
x = 6cos((17pi)/12) ≈ - 1.553 and
y = 6sin((17pi)/12) ≈ -5.796