What are the components of the vector between the origin and the polar coordinate $(9, \frac{17 π}{12})$ $(9, (17pi)/12)$ ?

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Answer 1 · 2017-12-03T08:34:45

$- 2.33 ˆ i - 8.69 ˆ j$ $-2.33hati-8.69hatj$

First convert the polar coordinate in a Cartesian coordinate. This can be done using:

$x = r cos (θ)$ $x=rcos(theta)$

$y = r sin (θ)$ $y=rsin(theta)$

$x = 9 cos (\frac{17 π}{12}) = - 2.33$ $x= 9cos((17pi)/12)=-2.33$

$y = 9 sin (\frac{17 π}{12}) = - 8.69$ $y= 9sin((17pi)/12)=-8.69$

Cartesian coordinates:

$(- 2.33, - 8.69)$ $( -2.33 , -8.69 )$

Vector components.

$x = - 2.33 ˆ i$ $x=-2.33hati$

$y = - 8.69 ˆ j$ $y=-8.69hatj$

$:.$

$-2.33hati-8.69hatj$

What are the components of the vector between the origin and the polar coordinate (9, (17pi)/12)(9,17π12)(9, (17pi)/12)?