What are the components of the vector between the origin and the polar coordinate #(-9, (5pi)/4)#?

1 Answer
bhaskar m.
Aug 16, 2017

The x-component and the y-component are both #\frac{9sqrt2}2#

Explanation:

To find the components of a vector given the polar coordinate creating the vector, you do the following:

#(r, \theta) =>(rcos(\theta), rsin(\theta))#

In this case:

#(-9, (5pi)/4) => (-9cos((5pi)/4), -9sin((5pi)/4))#
#=> (\frac{9sqrt2}2, \frac{9sqrt2}2)#

So the x-component and the y-component are both #\frac{9sqrt2}2#

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