What are the components of the vector between the origin and the polar coordinate $(-9, (5pi)/4)$ ?

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Answer 1 · 2017-08-16T00:25:11

The x-component and the y-component are both $\frac{9sqrt2}2$

To find the components of a vector given the polar coordinate creating the vector, you do the following:

$(r, \theta) =>(rcos(\theta), rsin(\theta))$

In this case:

$(-9, (5pi)/4) => (-9cos((5pi)/4), -9sin((5pi)/4))$
$=> (\frac{9sqrt2}2, \frac{9sqrt2}2)$

So the x-component and the y-component are both $\frac{9sqrt2}2$

What are the components of the vector between the origin and the polar coordinate (-9, (5pi)/4)(-9, (5pi)/4)?