What are the components of the vector between the origin and the polar coordinate $(- 8, \frac{13 π}{12})$ $(-8, (13pi)/12)$ ?

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Answer 1 · 2017-11-05T11:52:44

$7.727 ˆ i + 2.071 ˆ j$ $7.727hati+2.071hatj$

First convert the polar coordinate into a Cartesian coordinate. This can be done using:

$x = r cos (θ)$ $x=rcos(theta)$

$y = r sin (θ)$ $y=rsin(theta)$

$:.$

$x= -8(cos((13pi)/12))=7.727$ (3 .d.p)

$y=-8(sin((13pi)/12))=2.071$ (3 .d.p)

$7.727hati+2.071hatj$

What are the components of the vector between the origin and the polar coordinate (-8, (13pi)/12)(−8,13π12)(-8, (13pi)/12)?