What are the components of the vector between the origin and the polar coordinate (6, (3pi)/4)(6,3π4)?

1 Answer
Feb 12, 2016

((-3sqrt2),(3sqrt2))

Explanation:

using the formulae that links Polar to Cartesian coordinates.

• x = rcostheta

• y = rsintheta

in this question: r = 6 and theta = (3pi)/4

rArr x = 6cos((3pi)/4) = 6.(- 1/sqrt2) = -3sqrt2

[note : 1/sqrt2 = sqrt2/(sqrt2 .sqrt2) = 1/2 sqrt2]

and using exact values for cos((3pi)/4)color(black)(" and ") sin((3pi)/4)

rArr y = 6sin((3pi)/4) = 6.(1/sqrt2) = 3sqrt2