What are the components of the vector between the origin and the polar coordinate (6, (3pi)/4)(6,3π4)?
1 Answer
Feb 12, 2016
((-3sqrt2),(3sqrt2))
Explanation:
using the formulae that links Polar to Cartesian coordinates.
• x = rcostheta
• y = rsintheta in this question: r = 6 and
theta = (3pi)/4
rArr x = 6cos((3pi)/4) = 6.(- 1/sqrt2) = -3sqrt2 [note :
1/sqrt2 = sqrt2/(sqrt2 .sqrt2) = 1/2 sqrt2] and using exact values for
cos((3pi)/4)color(black)(" and ") sin((3pi)/4)
rArr y = 6sin((3pi)/4) = 6.(1/sqrt2) = 3sqrt2