What are the components of the vector between the origin and the polar coordinate (2, (-5pi)/6)(2,5π6)?

1 Answer
Sep 5, 2016

((-sqrt3),(-1))

Explanation:

To convert from color(blue)"polar to cartesian coordinates"

That is (r,theta)to(x,y)

color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta , y=rsintheta)color(white)(a/a)|)))

here r = 2 and theta=-(5pi)/6

rArrx=2cos(-(5pi)/6)" and " y=2sin(-(5pi)/6)

color(orange)"Reminder"

color(red)(|bar(ul(color(white)(a/a)color(black)(cos(-(5pi)/6)=-cos(pi/6))color(white)(a/a)|)))

and color(red)(|bar(ul(color(white)(a/a)color(black)(sin(-(5pi)/6)=-sin(pi/6))color(white)(a/a)|)))

rArrx=-2cos(pi/6)=-2xxsqrt3/2=-sqrt3

and y=-2sin(pi/6)=-2xx1/2=-1

Thus the components of the vector are ((-sqrt3),(-1))