What are the components of the vector between the origin and the polar coordinate (2, (-5pi)/6)(2,−5π6)?
1 Answer
Sep 5, 2016
Explanation:
To convert from
color(blue)"polar to cartesian coordinates" That is
(r,theta)to(x,y)
color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta , y=rsintheta)color(white)(a/a)|))) here r = 2 and
theta=-(5pi)/6
rArrx=2cos(-(5pi)/6)" and " y=2sin(-(5pi)/6)
color(orange)"Reminder"
color(red)(|bar(ul(color(white)(a/a)color(black)(cos(-(5pi)/6)=-cos(pi/6))color(white)(a/a)|))) and
color(red)(|bar(ul(color(white)(a/a)color(black)(sin(-(5pi)/6)=-sin(pi/6))color(white)(a/a)|)))
rArrx=-2cos(pi/6)=-2xxsqrt3/2=-sqrt3 and
y=-2sin(pi/6)=-2xx1/2=-1 Thus the components of the vector are
((-sqrt3),(-1))