What are the components of the vector between the origin and the polar coordinate (-8, (-7pi)/6)?

1 Answer
MrsRudolph221
Feb 17, 2018

The formula is (r*cos(theta),r*sin(theta)).

Explanation:

Calculate -8*cos((-7pi)/6) first. Do you understand the angle and its position? It is in Quadrant II, like -210 ^@ or 150^@.![https://www.wyzant.com/resources/lessons/math/trigonometry/unit-circle](useruploads.socratic.org)
The acute angle is 30^@, and the associated cosine value is -sqrt(3)/2 .
![https://www.wyzant.com/resources/lessons/math/trigonometry/unit-circle](useruploads.socratic.org)
Take -8 times the cosine value: (-8*-sqrt(3))/2 =(8sqrt3)/2=4sqrt3.

Repeat the procedure for -8*sin((-7pi)/6)=-8*1/2=-4.

Related questions
See all questions in Component Vectors
Impact of this question
4004 views around the world
You can reuse this answer
Creative Commons License