What are the components of the vector between the origin and the polar coordinate $(-1, (-3pi)/4)$ ?

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Answer 1 · 2016-05-29T11:03:11

$x=sqrt2/2$

$y=sqrt2/2$

Given $r=-1$ and $theta=(-3pi)/4$

$x=r*cos theta=(-1)*cos ((-3pi)/4)=(-1)((-1)/sqrt2)=sqrt2/2$

$y=r*sin theta=(-1)*sin ((-3pi)/4)=(-1)((-1)/sqrt2)=sqrt2/2$

God bless....I hope the explanation is useful.

What are the components of the vector between the origin and the polar coordinate (-1, (-3pi)/4)(-1, (-3pi)/4)?