What are the components of the vector between the origin and the polar coordinate $(9, (-pi)/4)$ ?

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Answer 1 · 2016-03-25T13:08:49

$x=(9sqrt2)/2$
$y=(-9sqrt2)/2$

Given $(r, theta)=(9, -pi/4)$

$x=r cos theta=9*cos (-pi/4)$
$x=9*1/sqrt2=9/sqrt2=(9*sqrt2)/(sqrt2)^2=(9sqrt2)/2$

$y=r sin theta=9*sin (-pi/4)$
$y=9*-1/sqrt2=-9/sqrt2=(-9*sqrt2)/(sqrt2)^2=(-9sqrt2)/2$

God bless....I hope the explanation is useful.

What are the components of the vector between the origin and the polar coordinate (9, (-pi)/4)(9, (-pi)/4)?