What are the components of the vector between the origin and the polar coordinate $(6, \frac{- 3 π}{8})$ $(6, (-3pi)/8)$ ?

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Answer 1 · 2016-04-18T18:01:21

$6 cos (\frac{3 π}{8}) i - 6 sin (\frac{3 π}{8}) j$ $6 cos((3pi)/8)i -6sin((3pi)/8)j$

Corresponding cartesean coordinates would be $6 cos (\frac{- 3 π}{8}), 6 sin (\frac{- 3 π}{8})$ $6 cos((-3pi)/8), 6 sin ((-3pi)/8)$

Or $6 cos (\frac{3 π}{8}), - 6 sin (\frac{3 π}{8})$ $6 cos((3pi)/8), -6sin((3pi)/8)$

The vector in component form would be

$6 cos (\frac{3 π}{8}) i - 6 sin (\frac{3 π}{8}) j$ $6 cos((3pi)/8)i -6sin((3pi)/8)j$

What are the components of the vector between the origin and the polar coordinate (6,−3π8)(6, (-3pi)/8)?