WeUsing the x-intercept and y-intercept, how do you graph 2x-3y=5?

2 Answers
LM
Dec 4, 2016

graph{2x-3y=5 [-10, 10, -5, 5]}

equation: y=(2x-5)/3

Explanation:

the equation can be converted into y=mx+c:

2x - 3y = 5

(-2x)

-3y = -2x + 5

(/3)

-y= (-2x+5)/3

(*-1)

y= -(-2x+5)/3

y= (2x-5)/3

Jim G.
Dec 4, 2016

"Plot the points " (0,-5/3)" and " (5/2,0)

Explanation:

When the line with given equation crosses the y-axis the corresponding x-coordinate at this point will be zero.
Substituting x = 0 into the equation gives the y-intercept.

(2xx0)-3y=5rArr-3y=5rArry=-5/3

rArr(0,-5/3)" is the point on the y-axis"

Similarly when the line crosses the x-axis the corresponding
y-coordinate at this point will be zero. Substituting y = 0 into the equation gives the x-intercept.

2x-(3xx0)=5rArr2x=5rArrx=5/2

rArr(5/2,0)" is the point on the x-axis"

Plot these 2 points and draw a straight line through them.
graph{2/3x-5/3 [-10, 10, -5, 5]}

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