Vanillin, $C_8H_8O_3$ , occurs naturally in vanilla extract and is used as a flavoring agent. A 39.1-mg sample of vanillin was dissolved in 168.5 mg of diphenyl ether, ( $C_6H_5)_2O$ . What is the molality of vanillin in the solution?

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Answer 1 · 2018-01-15T06:56:29

$"Molality"="Moles of solute"/"Kilograms of solvent"$

We get approx. $1.5*mol*kg^-1$

And so we set up the quotient....

$"Molality"=((39.1xx10^-3*g)/(152.15* g*mol^-1))/(168.5*mg*10^-6*kg*mg^-1)=??*kg*mol^-1$

Vanillin, C_8H_8O_3C_8H_8O_3, occurs naturally in vanilla extract and is used as a flavoring agent. A 39.1-mg sample of vanillin was dissolved in 168.5 mg of diphenyl ether, (C_6H_5)_2OC_6H_5)_2O. What is the molality of vanillin in the solution?