This appears to be a limiting reactant problem.
1. Write the balanced equation
"2NaCN" + "H"_2"SO"_4 → "Na"_2"SO"_4 + "2HCN"2NaCN+H2SO4→Na2SO4+2HCN
2. Calculate the moles of "Na"_2"SO"_4Na2SO4 formed from the "NaCN"NaCN
"Moles of Na"_2"SO"_4 = 5.93 color(red)(cancel(color(black)("g NaCN"))) × (1 color(red)(cancel(color(black)("mol NaCN"))))/(49.01 color(red)(cancel(color(black)("g NaCN")))) × (1 "mol Na"_2"SO"_4)/(2 color(red)(cancel(color(black)("mol NaCN")))) = "0.060 50 mol Na"_2"SO"_4
3. Calculate the moles of "Na"_2"SO"_4 formed from the "H"_2"SO"_4
"Moles of Na"_2"SO"_4 = 8.45 color(red)(cancel(color(black)("g H"_2"SO"_4))) × (1 color(red)(cancel(color(black)("mol H"_2"SO"_4))))/(98.08 color(red)(cancel(color(black)("g H"_2"SO"_4)))) × (1 "mol Na"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol H"_2"SO"_4)))) = "0.086 15 mol Na"_2"SO"_4
4. Identify the limiting reactant
The limiting reactant is "NaCN", because it produces the fewest moles of product.
5. Calculate the mass of "Na"_2"SO"_4
"Mass of Na"_2"SO"_4 = "0.060 50" color(red)(cancel(color(black)("mol Na"_2"SO"_4))) × ("142.04 g Na"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol Na"_2"SO"_4)))) = "8.59 g Na"_2"SO"_4