Using algebra, how do you find the smallest three consecutive integers whose sum is greater than 20?
1 Answer
Nov 16, 2016
Find that the three integers are:
Explanation:
Suppose the middle consecutive integer is
Then we want:
#20 < (n-1) + n + (n+1) = 3n#
Dividing both ends by
#n > 20/3 = 6 2/3#
So the smallest integer value of
