There is a normal distribution with min = 4, max = 16 and mean = 10. What is the standard deviation?

Question

Use the 68-95-99.7 rule.

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Answer 1 · 2017-02-12T05:53:11

$sigma=2$

It is a Normal Distribution.

The extreme values are expected to fall
3 Standard Deviation Distance on either side of the mean.

Then [look at the diagram also the z value of 4 is -3 and the z value of 16 is 3.

$z=(x-barx)/sigma$

At $x=16; z=(16-10)/sigma$

At $x=16; z=3$

Then -

$z=(16-10)/sigma$
$3=(16-10)/sigma$
$3sigma=16-10$
$sigma=6/3=2$
$sigma=2$