The velocity of an object with a mass of #3 kg# is given by #v(t)= 6 t^2 -4 t #. What is the impulse applied to the object at #t= 3 #?

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The velocity of an object with a mass of #3 kg# is given by #v(t)= 6 t^2 -4 t #. What is the impulse applied to the object at #t= 3 #?

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Answer 1 · 2016-02-13T21:33:18

#F*t=3*42=126 N.s#

Explanation:

#F=(d P)/(d t)#
#F*d t=d P#
#F*d t=d(m v)#
#F*d t=m d v#
#d v=(12t-4)*d t#
#F*d t=m*(12t-4)*d t#
#int F*d t=int m*(12t-4)*d t#
#F*t=m int (12t-4)*d t#
#F*t=3(6t^2-4t)#
#F*t=3(54-12)#
#F*t=3*42=126 N.s#

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The velocity of an object with a mass of #3 kg# is given by #v(t)= 6 t^2 -4 t #. What is the impulse applied to the object at #t= 3 #?

1 Answer

Explanation:

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