The sum of three consecutive even #s is 144; what are the numbers?

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The sum of three consecutive even #s is 144; what are the numbers?

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Answer 1 · 2016-05-30T21:00:41

They are 46, 48, 50.

Explanation:

An even number is a multiple of $2$ , then can be written as 2n. The next even number after $2n$ is $2n+2$ and the following is $2n+4.$
So you are asking for which value of $n$ it you have

$(2n)+(2n+2)+(2n+4)=144$

I solve it for $n$

$6n+6=144$
$n=138/6=23$ .

The three numbers are

$2n=2*23=46$
$2n+2=46+2=48$
$2n+4=46+4=50$

Answer 2 · 2016-05-30T21:03:17

The numbers are 46, 48 and 50.

Explanation:

First define the consecutive even numbers:

Even numbers, such as 8, 10, 12 etc. differ by 2.

We could call the numbers $x, x+2 and x+4$ , but there is no guarantee that x is even.

However, an even number can be divided by 2, so any number given as $2x$ is definitely even.

SO, let the consecutive even numbers be $2x, 2x + 2 and 2x + 4$
Their sum is 144, so write an equation:

$2x + (2x + 2) + (2x + 4) = 144$

$6x + 6 = 144$
$6x = 138$
$x = 23$

However, we defined the first even number as $2x$ .

$2 xx 23 = 46$

The numbers are 46, 48 and 50.

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The sum of three consecutive even #s is 144; what are the numbers?

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