The sum of the squares of two positive numbers is 9,so how much will the sum of their cubes be??

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The sum of the squares of two positive numbers is 9,so how much will the sum of their cubes be??

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Answer 1 · 2018-05-24T15:02:29

$27$ $27$

Explanation:

$x^{2} + y^{2} = 9$ $x^2+y^2=9$

What squares can add up to 9?

$0 + 9 = \sqrt{0} + \sqrt{3}$ $0 + 9 =sqrt 0 + sqrt3$ Works!
$1 + 8$ $1 + 8$ Neither are perfect squares
$2 + 7$ $2 +7$ Neither are perfect squares
$3 + 6$ $3 +6$ Neither are perfect squares
$4 + 5$ $4 +5$ Neither are perfect squares
now repeats...

so only $0^{2} + 3^{2}$ $0^2+3^2$ works

$0^{3} + 3^{3} = 27$ $0^3+3^3 = 27$

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The sum of the squares of two positive numbers is 9,so how much will the sum of their cubes be??

1 Answer

Explanation:

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