The sum of four consecutive integers is -2. What are the 4 integers?

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Answer 1 · 2016-06-02T21:09:11

The four integers are:

$- 2, - 1, 0, 1$ $-2, -1, 0, 1$

Suppose the integers are $n, (n + 1), (n + 2), (n + 3)$ $n, (n+1), (n+2), (n+3)$

Then we are given:

$- 2 = n + (n + 1) + (n + 2) + (n + 3) = 4 n + 6$ $-2 = n+(n+1)+(n+2)+(n+3) = 4n+6$

Subtract $6$ $6$ from both ends and transpose to get:

$4 n = - 8$ $4n = -8$

Divide both sides by $4$ $4$ to get:

$n = - 2$ $n = -2$

So the four integers are:

$- 2, - 1, 0, 1$ $-2, -1, 0, 1$