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The square root of 60 is between what 2 integers?

1 Answer

Oct 16, 2015

$7 < \sqrt{60} < 8$ $7 < sqrt(60) < 8$

Explanation:

$7^{2} = 49 < 60 < 64 = 8^{2}$ $7^2 = 49 < 60 < 64 = 8^2$

So

$7 < \sqrt{60} < 8$ $7 < sqrt(60) < 8$

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