The molecular weight of Na is 58.44 grams/mole. To prepare a 0.50 M solution: how many grams of NaCI would you need in 1,000 mL of water?

1 Answer
anor277
Aug 18, 2016

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#, so here we need #29.22*g# of #NaCl#

Explanation:

And thus, #(29.22*g)/(58.44*g*mol^-1)xx1/(1*L)# #=# #0.500*mol*L^-1#.

You might ask as to whether the volume of water would change (up or down upon dissolution of the salt. The volume change would be imperceptible.

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