The mean of eight numbers is 41. The mean of two of the numbers is 29. What is the mean of the other six numbers?

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Answer 1 · 2017-02-11T19:49:39

Meanof the six numbers is $\frac{270}{6} = 45$ $" "270/6 = 45$

There are 3 different sets of numbers involved here.
A set of six, a set of two and the set of all eight.

Each set has its own mean.

$mean = \frac{Total}{number of numbers}$ $"mean" = "Total"/"number of numbers"" "$ OR $M = \frac{T}{N}$ $M = T/N$

Note that if you know the mean and how many numbers there are, you can find the total.

$T = M \times N$ $T=M xxN$

You can add numbers, you can add totals, but you may not add means together.

So, for all eight numbers: The total is $8 \times 41 = 328$ $8 xx 41 = 328$

For two of the numbers: The total is $2 \times 29 = 58$ $2xx29 = 58$

Therefore the total of the other six numbers is $328 - 58 = 270$ $328-58 = 270$

The mean of the six numbers $= \frac{270}{6} = 45$ $=270/6 = 45$